Nicholson Canyon Simulation

From Gerris

Revision as of 23:02, 4 August 2011 EmilyMLane (Talk | contribs) (→Creating Solid Block) ← Previous diff		Revision as of 04:05, 9 August 2011 EmilyMLane (Talk | contribs) (→Creating Solid Block) Next diff →
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	<source lang=bash>		<source lang=bash>
	# Generating points using .awk file		# Generating points using .awk file
-	awk -f nic holson.awk > points.tmp	+	awk -f nicholson.awk > points.tmp
	# Delaunay triangulation and transformation using gts tools		# Delaunay triangulation and transformation using gts tools
	( wc points.tmp | awk '{print $1" 0 0"}'; cat points.tmp ) | gtsdelaunay -d | gtstransform --rx=-90 > nichol_test.gts		( wc points.tmp | awk '{print $1" 0 0"}'; cat points.tmp ) | gtsdelaunay -d | gtstransform --rx=-90 > nichol_test.gts

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Revision as of 04:05, 9 August 2011

Creating Solid Block

# Generating points using .awk file
awk -f nicholson.awk > points.tmp
# Delaunay triangulation and transformation using gts tools
( wc points.tmp | awk '{print $1" 0 0"}'; cat points.tmp ) | gtsdelaunay -d | gtstransform  --rx=-90 > nichol_test.gts
# Shifting points to the domain boundary
sed -e "s/ -0.0168/0/g" < nichol_test.gts > nichol_testout.gts

The .awk file used to generate the points is

BEGIN {
          a=0.272
          b=1.7
          alpha=atan2(a,b);
          h=a*cos(alpha);
          l1=b*cos(alpha);
          l2=a*sin(alpha);
 
          for (k=0; k <= 100; k++) {
            for (i=-1; i <= 100; i++) { printf("%5.4f %5.4f %5.4f\n",l1*i/100, -
0.85+1.7*k/100 , h*i/100) }
            for (i=1; i <= 101; i++) { printf("%5.4f %5.4f %5.4f\n",l1+l2*i/100,
 -0.85+1.7*k/100, h*(1-i/100)) }
          }
 
 
          dx=1.0e-4
          k=0.
          j=-1.
          for (i=-1; i <= 100; i++) { printf("%5.4f %5.4f %5.4f\n",l1*i/100, -0.
85+1.7*k/100-dx,h*j/100) }
          for (i=1; i <= 101; i++) { printf("%5.4f %5.4f %5.4f\n",l1+l2*i/100, -
0.85+1.7*k/100-dx,h*j/100) }
 
          k=100.
          for (i=-1; i <= 100; i++) { printf("%5.4f %5.4f %5.4f\n",l1*i/100, -0.
85+1.7*k/100+dx,h*j/100) }
          for (i=1; i <= 101; i++) { printf("%5.4f %5.4f %5.4f\n",l1+l2*i/100, -
0.85+1.7*k/100+dx,h*j/100) }
}